Math, asked by Anonymous, 3 months ago

what.is.the.square.root.of.√-16...wrong.=100.answer.report....not.tell.4....​

Answers

Answered by praseethanerthethil
2

Answer:

.

Square Root Of 6Square root of 6 can be easily found by using any of the methods to solve square roots. sqrt(6)= 2.44948974278 or √6 = 2.44948974278.To find Root 6 one can refer to the methods of simplifying square roots. √a.b = √a * √b.

Square Root Of 6Square root of 6 can be easily found by using any of the methods to solve square roots. sqrt(6)= 2.44948974278 or √6 = 2.44948974278.To find Root 6 one can refer to the methods of simplifying square roots. √a.b = √a * √b.To write this equation for the square root of 6 simplification, we will get:

Square Root Of 6Square root of 6 can be easily found by using any of the methods to solve square roots. sqrt(6)= 2.44948974278 or √6 = 2.44948974278.To find Root 6 one can refer to the methods of simplifying square roots. √a.b = √a * √b.To write this equation for the square root of 6 simplification, we will get:√6= √2 * √3.

Answered by Anonymous
3

Answer:

=..ANSWER

The answer is option D

Speed of 1

st

clock =58min/hr

Speed of 2

nd

clock =61min/hr [Since it gains 2min in 2hrs, it should gain 1min in 1hr]

Relative velocity of 2

nd

clock wrt 1

st

=61−58=3min/hr

Relative distance travelled by the 2

nd

clock wrt 1

st

by the time both are stopped =1hr6min=66min

Time taken by the 2

nd

clock wrt 1

st

to cover 66min=66/3=22hours

In those 22 hours, mins covered by the 1

st

clock =22×58=1276

The actual mins elapsed in those 22hours=22×60=1320

∴ Number of mins the 1

st

clcok is behind the correct time=1320−1276=44mins

⇒ If the time on the 1

st

clock is 9am, then the correct time is 9:44am

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