Question

what is the standard form of ‐112/128​

Answer 1

Answer:

-7/8

Step-by-step explanation:

-112/128 divided by 16/16 = -7/8

Answer 2

$Given \: rational \: number = \frac{-112}{128}$

/* To write standard form of a rational number , we have to find HCF of Numerator and denominator*/

$112 = 2^{4} \times 7$

$128 = 2^{7}$

$HCF \: of \: 112 \:and\:128 = 2^{4} = \pink {16}$

/* Dividing numerator and denominator by HCF,we get */

$\red { Standard \:form \: of \: \frac{-112}{128} }\\= \frac{- 16 \times 7 }{ 16 \times 8} \\= \frac{ \frac{-16\times 7}{16}}{\frac{16\times 8}{16}} \\= \frac{-7}{8}$

Therefore.,

$\red { Standard \:form \: of \: \frac{-112}{128} }\green { = \frac{-7}{8}}$

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