Math, asked by ravisuganya62, 9 months ago

what is the standard form of -18/-42​

Answers

Answered by alisha5654
4

Answer:

3/7

Step-by-step explanation:

-18/-42=18/42(here - and - cancelled each other)

now the standard form of 18/42

18and 42 when divided by their HCF 3

=6/14

then 6and 14 both are divided by their HCF 2 =3/7

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Answered by payalchatterje
0

Answer:

The standard form of -18/-42 is  \frac{3}{7}

Step-by-step explanation:

Here given,

  \frac{ - 18}{ - 42}

This is a problems of fraction of Algebra.

We need to simplify it.

First we are factorising 18 and 42.

By prime factorisation,

18 = 2 \times 3 \times 3 \\ 42 = 2 \times 3 \times 7

So,

( \frac{ - 18}{ - 42} ) =  \frac{2 \times 3 \times 3}{2 \times 3 \times 7}  \\  =  \frac{3}{7}

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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