Question

what is the standard form of 9x²-6x+1=0?​

Answer 1

Answer:

9^{2} - 6x + 1 =

09x 2−6x+1=0

9x {}^{2} - (3 + 3)x + 1 = 09x 2

−(3+3)x+1=0

9^{2} - 3x - 3x + 1 =

09x 2 −3x−3x+1=0

3x(3x - 1) - 1(3x - 1) = 03x(3x−1)−1(3x−1)=0

(3x - 1)(3x - 1) = 0(3x−1)(3x−1)=0