Question

What is the state of hybridization of xenon and shapes of the following molecule
(a) XeF2
(b)XeO3
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Answer 1

Answer:

In xenon tetrafluoride, the hybridization takes place in the central atom which is Xenon (Xe). If we look at the valence shell of Xe there are a total of six electrons in the 5p orbital and two electrons in the 5s orbital. If we observe the 5th shell then there are the d orbital and f orbital in which no electrons are present. In the formation of XeF4, two of the 5p orbital electrons which, in the excited state move to fill the vacant 5 d orbitals. As a result, there are 4 unpaired electrons which include 2 in 5p and 2 in 5d orbitals. This results in sp3d2 hybridization.

In the case of fluorine, four F atoms bond with these four half filled orbitals. These fluorine atoms will then be placed on either side of the central atom.

Answer 2

Explanation:

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