What is the strength in gm/litre of solution of h2so4,12ml of which neutralizes 15 ml of n/10 naoh solution?
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Answer:
Explanation:
H2SO4 : NaOH
N1V1=N2V2
X x 12 = N/10 x 15
X=(0.1 x 15)/12
X=0.125g/lit
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Explanation:
N=.125 g/l
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