Question

what is the structure of IF7 ?

Answer 1

Answer:

• In IF7, the core atom I(iodine) is linked to 7 fluorine atoms via 7 sigma bonds. So the steric number in this case is 7. As a result, IF7 I(iodine) hybridization is sp³d³.
• As a result, the electron pair as well as the molecular geometry are pentagonal bipyramidal.

Let us examine the structure:

Iodine (atomic number 53)

[E.C]=4d105s25p5 where E.C denotes electronic configuration

Consider the following image:

• Its electronic configuration changes in the first excited state:
• [E.C]=5s15p35d3
• As a result, there are 7 fluorine molecules. One enters 5s, three enter 5p, and three enter 5d.
• As a result, we can conclude that the hybridization is sp3d3. As a result, the structure is pentagonal bipyramidal.
• This is a pentagonal bipyramid. Furthermore, not all bonding angles are the same.
• Five electron pairs form a 72-degree angle with the same plane, while the other two form a 90-degree angle with it.
• Even bond lengths vary. The axial bonds are 186pm long, while the equatorial bonds are 179pm long.

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