Question

what is the subtraction of 2a+4b+3c and a+b+c ​

Answer 1

2a+3b+4c

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)=4a+8c

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)=4a+8cNow, we can perform the subtraction,

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)=4a+8cNow, we can perform the subtraction,∴ Required difference

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)=4a+8cNow, we can perform the subtraction,∴ Required difference=(4a+8c)−(2a−3b+4c)

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)=4a+8cNow, we can perform the subtraction,∴ Required difference=(4a+8c)−(2a−3b+4c)=4a+8c−2a+3b−4c

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).So, First we will do the sum of the three given polynomials,Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)=4a+8cNow, we can perform the subtraction,∴ Required difference=(4a+8c)−(2a−3b+4c)=4a+8c−2a+3b−4c=2a+3b+4c

Step-by-step explanation:

Hope it helps you