Question

What is the sum of 2+5+8+.....+152

Answer 1

The sum is 3927

an = a+(n-1)d

152=2+(n-1)3

n=51

Sn = n/2 [2a+(n-1)d]

Sn= 3927

Just put the values in the formula

a=2 ,n=51,d=3

Hope it helps you please mark as brainliest.

Answer 2

Answer:

3927

Step-by-step explanation:

• The last term is $152$. Hence, $a_{n} = 152$
• The first term is $2$. Hence, $a = 2$
• The difference between any two terms is $5-2=3$. Hence, $d = 3$

Substituting these values in the formula below to find out $n$.

⇒ $a_{n} = a + (n-1)d$

⇒ $152 = 2 + (n-1) \times 3$

⇒ $150 = 3n - 3$

⇒ $153 = 3n$

⇒ $n = \frac{153}{3}$

⇒ $n = 51$

Now, the sum of all the terms will be calculated by using the formula written below:

• $s_{n} = \frac{n}{2} [2a+(n-1) d]$

Substituting the values we get:

⇒ $s_{n} = \frac{51}{2} [2 \times 2 +(51 - 1)3]$

⇒ $s_{n} = \frac{51}{2} [4 + 150]$

⇒ $s_{n} = \frac{51}{2} \times 154$

⇒ $s_{n} = 51 \times 77$

⇒ $s_{n} = 3927$

Hence, the sum of all the terms given is $3927$.

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