What is the sum of 2 consecutive numbers the difference of whose squares is 19?
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Let be two consecutive no
x,x+1
Difference of whose square
=>(x+1)^2-x^2=19
=>x^2+2x+1-x^2=19
=>2x+1=19
=>2x=18
=>x=9
Sum of Two consecutive no are x,x+1
9+10=19
x,x+1
Difference of whose square
=>(x+1)^2-x^2=19
=>x^2+2x+1-x^2=19
=>2x+1=19
=>2x=18
=>x=9
Sum of Two consecutive no are x,x+1
9+10=19
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