Question

what is the sum of all natural numbers between 70 and 410 which are divisible by 5​

Answer 1

Answer:

FIRST WRITE THE QUESTION PROPERLY

Step-by-step explanation:

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Answer 2

Answer:

Ap : 75 , 80 , 85 ,90...............405

then- an = a + (n-1) d

405=75+(n-1) 5

405= 75+5n-5

405= 70+5n

405-70 = 5n

335 =5n

n= 335 /5

n = 67 .

then sum is

sn= n/2(a+(n-1)d)

sn = 67 /2(75+(67-1)5)

sn = 67/2 (75+ 66×5)

sn = 67/2( 75+ 330)

sn= 67/2 × 405

sn = 27135/2.