What is the sum of all of the odd numbers from 1 to 59?
Easy question
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If the legs of a right triangle are given by x2 - y2 and 2xy, then which expression equals the hypotenuse?
Can you have a right triangle where the lengths of the legs are whole numbers and the length of the hypotenuse is 23?
Answers
Answered by
9
a÷1
d=2
l=59
a+(n-1)d=59
(n-1)d=59-1=58
n-1=58
n=29+1=30
sum=30(1+59)/2
=900
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d=2
l=59
a+(n-1)d=59
(n-1)d=59-1=58
n-1=58
n=29+1=30
sum=30(1+59)/2
=900
Mark as brainliest plz
Answered by
4
The sum of first consecutive odd numbers is equal to n^2.
1+3+5+......+(2n-1)=n^2
Since 59=2(30)-1 (n=30)
In other words we are adding the first 30 odd numbers
When the result will be(30)^2 =900
1+3+5+......+(2n-1)=n^2
Since 59=2(30)-1 (n=30)
In other words we are adding the first 30 odd numbers
When the result will be(30)^2 =900
Similar questions
1 + 3 + 5 + ... + (2n - 1) = n²
Since:
59 = 2(30) - 1
n = 30
In other words, we are adding the first 30 odd numbers (1, 3, 5, ..., 55, 57, 59).
The result will be:
30² = 900
Answer:
900