Question

What is the sum of all positive integers less than 250 which are multiples of 8?​

Answer 1

Answer:

3968

Step-by-step explanation:

first multiple of 8 is 8

last multiple of 8 before 250 is 248

common difference is8

now

tn=a+(n-1)d

248= 8+(n-1)8

248= 8+8n-8

248= 8n

31= n

, sn=n/2{2a+(n-1)d)

= 31/2{2×8+(31-1)8}

= 31/2(16+30×8)

= 31/2(16+240

= 31/2× 256

= 31×128

= 3968

hence sum of all mutiples of 8 before 250 is 3968

.....666....

Answer 2

Answer:

3968 is your answer

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