what is the sum of all the numbers from 50 - 350 that are multiples of 6..and also write the 15th term
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multiplication of 6 are
54,60,66,72.......348
6(9,10,11.....57)
formala n(n+1)/2
57(58)/2 - 8(9)/2
54,60,66,72.......348
6(9,10,11.....57)
formala n(n+1)/2
57(58)/2 - 8(9)/2
kchandankhushi:
please ellaborate..i wanted the final answer
Answered by
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given 50,51,..................350
multiples of 6
54, 60, 66, ......................,342,348
here,
a=54, l=328, d=6
n = (l-a)/d + 1
= (348-54)/6 + 1
= 294/6 +1
= 49 + 1 = 50
Sn = n/2(l+a)
= 50/2(328+54)
= 25 * 382 = 9550
Tn = a + (n-1) d
T15 = 54 + (15-1)6
= 54+14*6
= 54 +84
= 138
multiples of 6
54, 60, 66, ......................,342,348
here,
a=54, l=328, d=6
n = (l-a)/d + 1
= (348-54)/6 + 1
= 294/6 +1
= 49 + 1 = 50
Sn = n/2(l+a)
= 50/2(328+54)
= 25 * 382 = 9550
Tn = a + (n-1) d
T15 = 54 + (15-1)6
= 54+14*6
= 54 +84
= 138
if you satisfy with this answer then pls. mark it has brainliest
it is a wrong answer ..i verified it..i will soon update the correct answer
sorry, instead 15, I substituted 50, now the answer will be correct. pls.check the answer
i got sum as 10050 and 15th term at 138..
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