Question

what is the sum of all the term between 1 to 1000 which is divisible by 3​

Answer 1

Answer:83667

Step-by-step explanation:

Here first term, a = 3

Second term = 9

Common difference, d = 6

Last term an = 999

a+(n-1)d = 999

3+(n-1)6 = 999

-3+6n = 999  

6n = 999+3 = 1002

n = 1002/6 = 167

Sum of n terms = (n/2)(a+an)

= (167/2)(3+999)

= 83667

Answer 2

Answer:

The answer is the number : 83667