Math, asked by jumaprakash402, 9 months ago

what is the sum of first n odd natural numbers? With detail explanation ​

Answers

Answered by abhi569
1

Answer:

Step-by-step explanation:

First odd number = 1

2nd odd number = 3

3rd odd number = 5

 first term = 1

 com. dif = 3 - 1 = 2

Therefore,

S = (n/2)[ 2a + (n - 1)d]

  = (n/2)[ 2(1) + (n - 1)2]

  = (n/2)[ 2 + 2n - 2]

  = (n/2)( 2n )

  = n²

Answered by ShauryaPratapSsingh
1

Step-by-step explanation:

given:

the first odd number is 1

second is 3

the third is 5 and so on...

here common difference is t2-t1

d = 2

therefore

S = n/2 [2a +(n -1) ×d]

S = n/2 [2×1 +(n-1)×2]

S = n/2 [2 + 2n - 2]

S = n/2 [ 2n]

S = n × n

S= n²

hope it's helpful for you

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