What is the sum of first 'n' odd positive integers?
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The sum of the first n even positive integers is p and the sum of the first n odd integers is q.
arohi777:
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The sum of first 'n' odd positive integers is n²
Given: First 'n' odd positive integers
To Find: The sum of first 'n' odd positive integers
Solution:
The first 'n' odd natural numbers are = 1 , 3 , 5 , 7 , 9 ,..., ((2n-1)
We can clearly see that this forms an arithmetic progession (AP).
a = 1, d = 2, tn = 2n - 1
The formula for sum of an AP is;
S = n/2 [ 2a + ( n - 1 )×d ]
Putting the respective values, we get;
⇒ S = n/2 [ 2 + 2n - 2 ]
⇒ S = n/2 [2n]
⇒ S = n²
Hence the sum of first 'n' odd positive integers is n²
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