What is the sum of first n positive integers?
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Answer:
For any positive integer n, the sum of the first n positive integers equals n(n+1)/2.
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Then the conclusion is that the property is true for every integer n greater than or equal to m. Example: Prove that the sum of the n first odd positive integers is n2, i.e., 1 + 3 + 5 + + (2n − 1) = n2.
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