what is the sum of first nerms of an ap
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Sum of n terms of AP is n/2(a+l).
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we all know in Ap is we have common difference d
lets say first term a second term a1= a+d third term a2= a+2d ....nth term an= a+(n-1)d
sum of these= a+a1+a2+...an= a+a+2d+a+3d......+a+(n-1)d-----1 rewrite terms in reverse order s= [a+(n-1)d]+[a+(n-2)d]+....+a] ----2
add 1 and 2 2s= n[2a+(n-1)d]
sum = n/2 [2a+(n-1)d]
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