Question

What is the sum of natural numbers between 100 and 500 which are divisibl
e by 4?

Answer 1

Answer:

The sum of natural numbers between 100 and 500 which are divisible by 4 is 29700.

Step-by-step explanation:

Here, a(First term) = 104

and an(Last term) = 496

and d = 4

So, an = a + (n - 1)d

=> 496 = 104 + (n - 1)×4

=> n - 1 = 98

=> n = 99

$So, \: Sum \: = \: \frac{n}{2} (a + an) \\ = \frac{99}{2} \times (104 + 496) \\ = \frac{99}{2} \times 600 \\ = 29700$

So, the sum of natural numbers between 100 and 500 which are divisible by 4 is 29700.

Mark As Brainliest

Answer 2

Answer:

S=300

Step-by-step explanation:

Natural numbers between 100 to 500 divisible by 4= (104,108,......, 496)

a=100

d=4

tn=500

tn=a+(n-1)d

496=100+(n-1)4

496-100=4n-4

396+4=4n

400=4n

n=100

Sn=n/2(t1+tn)

S100=100/2(104+496)

S100=50(600)

S100=30000

S=30000/100

S=300