what is the sum of the AP log X+log X2+ log X3+........+log X(n-1)?
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using the property LogX²= 2LogX
we get the sum as..
(1+2+3+4+...n-1) logx
the first summation is the sum of first n-1 natural numbers which is equal to (n)(n-1)/2
Hence the summation becomes log x^(n)(n-1)/2
we get the sum as..
(1+2+3+4+...n-1) logx
the first summation is the sum of first n-1 natural numbers which is equal to (n)(n-1)/2
Hence the summation becomes log x^(n)(n-1)/2
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