Math, asked by mousmidas6314, 1 year ago

What is the sum of the cubes of the first 3 odd prime numbers

Answers

Answered by sinhaankitalko
2

Answer:


Step-by-step explanation:

first 3 odd prime numbers=3,5,7

cubes of first 3 odd prime numbers=27,125,343

sum of cubes of first three odd numbers=27+125+343

                                                                   =495



hope it helps!!!! plzz mark brainliest


Answered by dikshaagarwal4442
0

Answer:

The sum of the cubes of the first 3 odd prime numbers = 495

Step-by-step explanation:

  • Prime number: The numbers which are divisible by 1 and the number itself is called prime numbers. 1 is not a prime number.

       Odd number: The number which can not be divided by 2 is called odd number.

  • First three numbers which are odd as well as prime are: 3, 5 and 7.

       Cube of 3 = 3³ = 3 × 3 × 3 = 27

       Cube of 5 = 5³ = 5 × 5 × 5 = 125

       Cube of 7 = 7³ = 7 × 7 × 7 = 343

     By adding them,  3³ + 5³ + 7³ = 27 + 125 + 343 = 495

  ∴ The sum of the cubes of the first 3 odd prime numbers = 495

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