Question

what is the sum of the even integers from 100 to 1000

Answer 1

Solving this question with AP :

Given,
$a = 100 \\ d = 1 \\ l = 1000 \\n = 900 \\ = \frac{n}{2} (a + l) \\ = \frac{900}{2}(100 + 1000) \\ = 450 \times 1100 \\ = 495000$
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