Math, asked by indeldashnprabha, 1 year ago

what is the sum of the exponents of the prime factorisation of 2700?

Answers

Answered by mysticd
3
2700= 2*2*3*3*3*5*5
= 2^2*3^3*5^2
sum of the exponents = 2+3+2=7
Answered by thirumal
3
2700=2*1350=2*2*675=2*2*5*135=2*2*5*5*27=2*2*5*5*3*9=2*2*5*5*3*3*3=2^2*3^3*5^2
=2+3+2=7
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