Question

what is the sum of the first 10th term of an A.P is 41,36,31,26....?​

Answer 1

Answer:

Step-by-step explanation:

sum of n terms of AP is denoted by the formula

$S_{n}=\frac{n}{2} (2a+(n-1) d)$ where a is the 1st term, n is the number of terms, d is difference and Sn is the sum of the series.

so, S = 10/2 [ 2 ×41 +(10-1)×(-5)]

S = 5 [ 82 + 9× (-5)]

S = 5 [ 82 -45]

S = 5 × 37

S = 185

Answer 2

Answer:

d is _4

10 term = a+9d

41+9×(-4)

41+_36=5ans