What is the sum of the first 1200 numbers that are multiples of 3
Answers
Answered by
0
Answer:
1200÷3=400
Step-by-step explanation:
when we fisrt multiply 3 ×400 then we get 1200 so the first no is 400
Answered by
0
Answer:
1961800
Step-by-step explanation:
n= 1200
d=3
a=3
Sn=n/2(a+l)
= 1200/2 (3+3600)
= 600(3603)
=1961800
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