What is the sum of the first 15 terms of an AP. 3,5.5,8,10.5,13........
Answers
Answered by
0
Step-by-step explanation:
Sum Sn= n/2[2a+(n-1)d]
a=3 d=2.5 n=15
Substituting,
Sn=15/2[2*3+(15-1)*2.5]
=15/2(6+14*2.5)
=15/2(6+35)
=15/2(41)
=7.5*41
=307.5
Answered by
0
Answer:
Given data:
a=3, n=15,d=2.5
Step-by-step explanation:
Tn = a+(n-1)d
T(15)=3+(15-1)2.5
T(15)=3+14*2.5
=3+35
T(15)=38
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