What is the sum of the first six multiples of 6
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Answered by
23
6+12+18+24+30+36=126
Hope this helps...
Hope this helps...
Answered by
3
a=6
d=6
Sn=n/2(2a+(n-1)d)
S6=6/2(2(6)+5(6)
S6=3(12+30)
=3*42
126
d=6
Sn=n/2(2a+(n-1)d)
S6=6/2(2(6)+5(6)
S6=3(12+30)
=3*42
126
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