Question

What is the sum of zeroes and product of zeroes of the polynomial p(x)= x^2-2x-8​

Answer 1

Step-by-step explanation:

Given that :

1. P(x) =x^2 - 2x-8

To Find:

sum and product of zeros

Solution :

As we know that f(x) =ax^2 +bx+c

And

$\alpha + \beta = \frac{ - b}{a} \\ \alpha \beta = \frac{c}{a}$

As p(x) =x^2 - 2x-8

Here a=1

b=-2

c = - 8

$\alpha + \beta = \frac{ - ( - 2)}{1} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \\ \\ \alpha \beta = \frac{ - 8}{1} \\ \: \: \: \: \: \: \: \: \: = - 8$