Question

What is the sum which one divided among A,B,C,D in proportion 2:3:5:8 provides Rs. 8420 less to D then what it provides to him when the proportion is 1/2:1/3:1/5:1/8.?

Answer 1

Answer:

Let us assume that, total sum is Rs.x .

Than,

→ share of D when divide in proportion 2 : 3 : 5 : 8 is = (8/2 + 3 + 5 + 8) of x = (8/18) of x = Rs.(4x/9)

now, Ratio in second time :-

→ A : B : C : D = 1/2 : 1/3 : 1/5 : 1/8

Taking LCM of denominators ,

→ A : B : C : D = (60 : 40 : 24 : 15) /120 = 60 : 40 : 24 : 15 .

So,

→ Share of D when divided in proportion 60 : 40 : 24 : 15 = 15/(60 + 40 + 24 + 15) of x = (15/139) of x = Rs.(15x/139)

now, given that, he gets Rs.8420 less in second share.

Therefore,

→ (4x/9) - (15x/139) = 8420

→ (139*4x - 135x) /1251 = 8420

→ 556x - 135x = 8420 * 1251

→ 421x = 8420 * 1251

dividing both sides by 421 ,

→ x = 20 * 1251

→ x = Rs.25,020 (Ans.)

Hence, the required sum is Rs.25,020 .

Step-by-step explanation:

Please mark as brainalist answer.