Question

What is the surface area of a cuboidal box whose length, breath & height are 16cm, 8cm and 6cm respectively?

Answer 1

Given :-

• Length of the Box = 16cm
• Breadth of the Box = 8cm
• Height of the Box = 6cm

To Find :-

• Surface Area of the Box

Solution :-

⟹ Surface Area of Box = 2( lb + bh + hl )

⟹ ⠀Surface Area = 2( 16 × 8 + 8 × 6 + 6 × 16 )

⟹ ⠀⠀Surface Area = 2( 128 + 48 + 96 )

⟹ ⠀⠀Surface Area = 2( 128 + 144)

⟹ ⠀⠀Surface Area = 2 × 272

⟹ ⠀⠀Surface Area of Box = 544cm²

Thus, Surface Area of Box = 544cm²

________________

★ Additional Info :

• T.S.A of cylinder = 2πrh + 2πr²
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Surface area of sphere = 4πr²
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

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Answer 2

Step-by-step explanation:

⠀━━━━━━━━━━━━━━━━━━━━━━━━

$\huge\pink{\mid{\fbox{\tt{QųEsTɪOη}}\mid}}$

Whatis the surface area of a cuboidal box whose length, breath & height are 16cm, 8cm and 6cm respectively?

⠀━━━━━━━━━━━━━━━━━━━━━━━━

$\huge{\underline{\mathrm{Given\: :}}}$

$\sf\red{Length \:of \:the \:Box = 16cm}$

$\sf\green{ Breadth\: of\: the \:Box = 8cm}$

$\sf\pink{ Height\: of\: the\: Box = 6cm}$

$\huge{\underline{\orange{\mathrm{To\: Find :}}}}$

Surface Area of the Box?

$\huge{\underline{\red{\mathrm{Solution\: }}}}$

$\sf\blue{⟼ Surface\: Area\: of \:Box = 2( lb + bh + hl )}$

$\sf\pink{⟼Surface \:Area = 2( 16 × 8 + 8 × 6 + 6 × 16 ) }$

$\sf\green{ ⟼Surface\: Area = 2( 128 + 48 + 96 )}$

$\sf\orange{⟼Surface \:Area = 2( 128 + 144) }$

$\sf\blue{ ⟼Surface\: Area = 2 × 272}$

$\sf\red{⟼Surface \:Area\: of\: Box = 544cm² }$

⠀━━━━━━━━━━━━━━━━━━━━━━━━

Therefore, The Surface Area of Box = 544cm²