Chemistry, asked by srikrishnakowtilya, 2 months ago

What is the temperature in the options given below. can increase air bubbles volume twice at constant pressure.
a. delta T = 2T2
b. delta T = 2T1
c. delta T = T2
d. delta T = T1​

Answers

Answered by samparaabhi
1

Answer:

option c

Explanation:

because the air bubbles pressure remains constant

Answered by archanajhaasl
0

Answer:

The correct answer among the given option is (d) i.e.ΔT=T₁.

Explanation:

At constant pressure, volume and temperature relation is given as,

\frac{V_1}{T_1}= \frac{V_2}{T_2}       (1)

Where,

V₁=initial volume of the bubble

T₁=initial temperature of the bubble

V₂=final volume of the bubble

T₂=final temperature of the bubble

Let's consider that,

V_1=V

V_2=2V

Let's consider the initial temperature of the bubble as T₁. By substituting the required values in the equation (1) we get;

\frac{V}{T_1}= \frac{2V}{T_2}

T_2=2T_1   (2)

An increase in temperature of the air bubble is given as,

\Delta T=T_2-T_1      (3)

By substituting equation (2) in equation (3) we get;

\Delta T=2T_1-T_1

\Delta T=T_1

Hence, the correct answer among the given option is (d) i.e.ΔT=T₁.

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