Question

what is the theoretical value of minimum of J(w) =w1^2+w2^2+4w1-6w2-7

Answer 1

Answer:

The minimum of J(w) is -20.

Step-by-step explanation:

Since we want to know what is the theoretical value of minimum of J(w)=w1^2+w2^2+4w1-6w2-7, we want to follow the steps bellow.

We first need to partially differentiating J(w) with respect to w1, keeping w2 as a constant term.

Then we will get that w1 = -2.

We now need to make the same but now to the w2 variable, and wil will conclude that w2 = 3.

Now, we just need to put the value of w1 and w2 in J(w) and you will get minimum value.

 = (-2)² + (3)² + 4(-2) - 6(3) - 7 = -20

Hence, the minimum of J(w) is -20.