Question

what is the time period of a simple pendulum? How would you calculate it experimentally? ​

Answer 1

A mass m suspended by a wire of length L is a simple pendulum and undergoes simple harmonic motion for amplitudes less than about 15º. The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.

Answer 2

$\huge\underline\bold\purple{AnswER}$

Question : 1

what is the time period of a simple pendulum?

Answer

The time taken by a freely oscillating pendulum to complete one. oscillation is called Time period Its SI unit is second (s) It is numerically. the reciprocal of frequency of oscillations..

A point mass attached to a light inextensible string and suspended from fixed support is called a simple pendulum. The vertical line passing through the fixed support is the mean position of a simple pendulum.

The vertical distance between the point of suspension and the centre of mass of the suspended body (when it is in mean position) is called the length of the simple pendulum denoted by L...

Question : 2

How would you calculate it experimentally?

Answer

For example, to calculate the experimental value for an experiment with results of 7.2, 7.2, 7.3, 7.5, 7.7, 7.8 and 7.9, add them all together first to arrive at a total value of 52.6 and then divide by the total number of trials – 7 in this case....

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