What is the torque of the force F=3i-2j+4k acting at a point r=2i+3j+5k about the origin
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Answer:
- 22 i - 7 j + 13 k
Explanation:
Given :
We know :
Torque τ = F × r
Now cross product of given vectors :
i j k
3 - 2 4
2 3 5
τ = [ ( - 10 - 12 ) i - ( 15 - 8 ) j + ( 9 - ( - 4 ) k ]
τ = - 22 i - 7 j + 13 k
Therefore , torque is - 22 i - 7 j + 13 k .
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