Question

What is the total number of atoms in 0.100 mol of pt(nh3)2cl2?

Answer 1

Answer:

66inches have a good mrng

Answer 2

The total number of atoms in 0.100 mol of $Pt(NH_3)_2Cl_2$ contains $6.625\times 10^{23}$ atoms

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$  of particles.

1 mole of $Pt(NH_3)_2Cl_2$ contains = 11 moles of atoms

1 mole of $Pt(NH_3)_2Cl_2$ contains = $6.023\times 10^{23}\times 11=66.25\times 10^{23}$  atoms

Thus 0.100 moles of $Pt(NH_3)_2Cl_2$ contains = $\frac{66.25\times 10^{23}}{1}\times 0.100=6.625\times 10^{23}$  atoms

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