What is the total surface area of cuboid whose dimensions are 11/2cm, 4cm, 21/2cm
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Answer:
Hola mate!!!
Step-by-step explanation:
Given:
The dimensions of cuboid are 11/2 cm× 4 cm× 21/2 cm
To find:
TSA of cuboid
Solution:
Let us take l , w and h as length, width and height of the cuboid.
l = 11/2 cm
w = 4cm
h = 21/2 cm
TSA of cuboid = 2 ( lw + wh +hl)
TSA = 2 ( 11/2×4 + 4×21/2 + 21/2×11/2)
= 2 ( 44/2 + 84 /2 + 231/4)
= 2 ( 22 + 42 + 231/4)
= 2 ( 88/4 + 168/4+ 231/4)
= 2 (487/4)
= 487/2
= 243.5 cm^2
The TSA of the cuboid is 243.5cm^2
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