Question

What is the total surface area of the box .length 9.0cm width 6.0 and height 10.2 cm

Answer 1

Answer:

Total Surface Area of the box (TSA) =414 cm^2

Step-by-step explanation:

GIVEN: Length(L) =9

Width/Breadth(b)=6

Height(h)=10.2

TO FIND: Total surface area(TSA)

TSA=2(L×b+b×h+h×L)

=2[(9×6)+(6×10.2)+(10.2×9)]

=2(54+61.2+91.8)

=2(207)

=414cm^2

HOPE IT HELPS

Answer 2

$\large \blue{\boxed{ \underbrace{ \sf \star Given : \implies}}}$

• Length of the box = 9.0cm
• Width of the box = 6.0cm
• Height of the box= 10.2cm

$\large \orange{\boxed{ \underbrace{ \sf \star To \: find : \implies}}}$

Total surface area of the box.

★Solution:-

$\text{We know that the box is in the shape of a cuboid.}$

$\text{Formula for to find TSA of a cuboid is.}$

$\large\boxed{ \sf TSA \: of \; a \: cuboid = 2(lw + wh+ hl)}$

$\text{Here, "l" = Length of the cuboid.}$

$\text{"w" = Width of the cuboid.}$

$\text{"h" = Height of the cuboid.}$

______________________

$\sf TSA \: of \; a \: cuboid = 2(lw + wh + hl)$

$\sf \implies 2[(9 \times 6) + (6 \times 10.2) + (10.2 \times 9)]$

$\sf \implies 2(54+ 61.2 + 91.8 )$

$\sf \implies 414cm^2$

Hope it helps