What is the total surface area of the cubical box which is opened from one side whose outer side is 5cm and thickness is 0.5cm?
Answers
Answered by
6
Lb+2(BH+HL) it is formula of open cubical box
3.0
Answered by
8
Question:
What is the total surface area of the cubical box which is opened from one side whose outer side is 5cm and thickness is 0.5cm?
Answer:
Length (l) = 5cm
Breadth (b) = 5cm
Height (h) = 5cm
TSA of cuboid = 2(l*b+b*h+h*l)
= 2 × (5 × 5 + 5 × 5 + 5× 5)
= 2 × (25 + 25 + 25)
= 2 × (75)
= 150 sq cm
Now , we know that box is open from top so we have to subtract Area of rectangle from TSA .
Area of rectangle = l × b
= 5 × 5
= 25 sq cm
The surface area of open cuboidal box
= TSA of cuboidal box - Area of rectangle
= 150 - 25
= 125 sq cm
Hence, Answer - 125 sq cm
HOPE ITS HELP YOU
THANK YOU
Similar questions