Question

What is the valu of Sin^4x+cos^4x

Answer 1

Answer:

$sin^{4} x+ cos^{4} x = \\ \\ = > (\sin^{2} x)^{2} +( \cos ^{2} x) ^{2} \\ \\ = > ( \sin ^{2} + \cos ^{2} x) ^{2} - 2 \sin ^{2} x \cos^{2}x \\ \\ \\ = > 1 - 2 \sin ^{2} x \cos ^{2} x$

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