what is the value of 0-1+2-3+4-5+6-7______+16-17+18-19+20.
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Answer:10
Step-by-step explanation:(2+4+6+.......+20) - (1+3+5+.......+19)
Now, we got two A.P.s
Let the number of terms in first A.P. be n
20 = 2 + (n - 1)(4 - 2)
20 = 2 + 2n - 2
20 = 2n
2n = 20
n = 10
Let the number of terms in second A.P. be m
19 = 1 + (m - 1)(3 - 1)
19 = 1 + 2m - 2
2m - 1 = 19
2m = 20
m = 10
sum of the series
10/2(2*2+(10-1)2) - 10/2(2*1+(10-1)2)
=5(4+9*2) - 5(2+9*2)
=5(4+18) - 5(2+18)
=5*22 - 5*20
=10
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