what is the value of 1+x/1-x⁴+x²/1+x²×x(1-x)?
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(1+x)/(1-x⁴)+x²/(1+x²) × x(1-x)
= 1/(1-x)(1+x²) + x²/(1+x²) × x(1-x)
= [1+x²(1-x)]/(1-x)(1+x²) × x(1-x)
= (1+x²-x³)/(1+x²) × x
sorry this is not possible
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