Question

what is the value of 1²+2²+3²+......+10²?​

Answer 1

The general formula for :

1^2 +2^2 + 3^2 +4^2…….+n^2=(n)(n+1)(2n+1)/6

So the ans to the given ques can be found out by substituting 10 in the above formula which gives

.

.

.

10*(10+1)*(20+1)/6

= 110*21/6

= 385

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Answer 2

Answer:

$\huge\bigstar\sf\purple{by / its / general / formula / Answer= / 385:}$