What is the value of 2 consecutive natural numbers, sum of whose squares is 145?
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Let the first no. be x
& the second no. be x+1
now according to the question
x²+(x+1)²=145
x²+x²+1+2x=145
2x²+2x+1-145=0
2x²+2x-144=0
x²+x-72=0
x²+9x-8x-72=0
x(x+9)-8(x+9)=0
(x-8)(x+9)=0
(x-8)=0
x=8
(x+9)=0
x=-9
⭐If The value of x we take 8
then x+1
=9
⭐If x=-9
x+1
=-9+1
=-8
@Altaf
& the second no. be x+1
now according to the question
x²+(x+1)²=145
x²+x²+1+2x=145
2x²+2x+1-145=0
2x²+2x-144=0
x²+x-72=0
x²+9x-8x-72=0
x(x+9)-8(x+9)=0
(x-8)(x+9)=0
(x-8)=0
x=8
(x+9)=0
x=-9
⭐If The value of x we take 8
then x+1
=9
⭐If x=-9
x+1
=-9+1
=-8
@Altaf
Answered by
0
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