What is the value of 22 x square + 6 root of 11 x minus 8 equal to?
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Answered by
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Answer:
22x2+6√11x-8 =0
=22x2-2√11+8√11-8=0
= 2√11x(√11x-1) + 8(√11x-1)=0
=(2√11x+8)(√11x-1)=0
=x=-8/2√11,1/√11
Answered by
0
Answer:
Answer given below
Step-by-step explanation:
22*2+6 sqrt 11*-8=0
z=2 sqrt 11x( sqrt 11x-1)+8( sqrt 11x-1)=0
=22*2-2 sqrt 11+8 sqrt 11-8=0
=(2 sqrt 11x+8 )( sqrt 11x-1)=0
= chi=-8/2 sqrt 11,1/ sqrt 1 1
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