Question

what is the value of √24+√32(√6+√8).... please answer me fast​

Answer 1

\begin{gathered}( \sqrt{24} + \sqrt{32}) \div ( \sqrt{6} + \sqrt{8} ) \\ \\ \\ = \frac{2 \sqrt{6 } + 2\sqrt{8 } }{ \sqrt{6} + \sqrt{8} } \\ \\ \frac{2( \sqrt{6} + \sqrt{8}) }{ \sqrt{6} + \sqrt{8} } \\ \\ = 2 \: ans..\end{gathered}

(

24

+

32

)÷(

6

+

8

)

=

6

+

8

2

6

+2

8

6

+

8

2(

6

+

8

)

=2ans..

please make me the brainlyest

Answer 2

$\huge { \red{ \boxed{ \green { \boxed{ \color{yellow}{ \boxed{ \color{silver}{ \boxed{ \pink { \boxed{ \color{skyblue}{ \boxed{ \color{maroon}{ \boxed{\bf \blue{ 16 + 2\sqrt{6} + 8\sqrt{3} }}}}}}}}}}}}} }}}$

Step-by-step explanation:

$\sqrt{24} + \sqrt{32} ( \sqrt{6} + \sqrt{8} ) \\ \\ = > \sqrt{24} + ( \sqrt{32} \times \sqrt{6)} + ( \sqrt{32} \times \sqrt{8} ) \\ \\ = > \sqrt{6 \times 4} + \sqrt{32 \times 6} + \sqrt{32 \times 8} \\ \\ = > \sqrt{6 \times {2}^{2} } + \sqrt{32 \times 2 \times 3} + \sqrt{16 \times 2 \times 8} \\ \\ = > 2 \sqrt{6} + \sqrt{64 \times 3} + \sqrt{16 \times 16} \\ \\ = > 2 \sqrt{6} + \sqrt{ {8}^{2} \times 3} + \sqrt{ {16}^{2} } \\ \\ = > 2 \sqrt{6} + 8 \sqrt{3} + 16 \\ \\ \red{ = >16 + 2\sqrt{6} + 8 \sqrt{3} }$

So,

the value is 16 + 2√6 + 8√3.

Hope it helps.

#BeBrainly :-)