What is the value of (-√3+i)^53
In terms of i
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mod=r=sart(3+1)=2. theta=atan(1/- root3)=5pi/6.
Ans is 2^53*(cos 53*5pi/6+i sin 53*5pi/6)
Ans is 2^53*(cos 53*5pi/6+i sin 53*5pi/6)
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