Question

What is the value of 8sec²60°-8tan²60° ?




please solve this ... ​

Answer 1

Answer:

tanx)

2

=(secx)

2

-1

So, 8 [(secx)

2

-1]+9=6secx

8(secx)

2

-8+9=6secx

6secx=8(secx)

2

+1

8(secx)

2

-6secx+1=0

So, we get a quadratic in "secx".

on solving we get, there does not exist any value of 'x' for which the aove equation is satisfied.

Therefore, zero solution.

(sec⁡