what is the value of (a+1/a)^2=?
Answers
Answered by
0
Answer:
a2+1/a2+2*a *1/a
a2+1/a2
a4+1/a2
Answered by
1
Answer:
4
Step-by-step explanation:
Given, a = 1 - √2
⇒ a = 1 - √2
⇒ 1 / a = 1 / ( 1 - √2 )
Multiplying and dividing RHS by 1 + √2 :
⇒ 1 / a = ( 1 + √2 ) / { ( 1 + √2 ) ( 1 - √2 ) }
⇒ 1 / a = ( 1 + √2 ) / { ( 1 )^2 - ( √2 )^2 } { Using ( a + b )( a - b ) = a^2 -b^2}
⇒ 1 / a = ( 1 + √2 ) / ( 1 - 2 )
⇒ 1 / a = ( 1 + √2 ) / ( - 1 )
⇒ 1 / a = - 1 - √2
Therefore,
⇒ a - 1 / a = 1 - √2 - ( - 1 - √2 )
⇒ a - 1 / a = 1 - √2 + 1 + √2
⇒ a - 1 / a = 2
⇒ ( a - 1 / a )^2
= 4
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