What is the value of a and b if 4a18b is exactly divisible by 101?
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Answer:well i m just guessing it but maybe a=9 and b=7 will be best valueswell here is solution-for divisblity by 101 form block of 2 digit right to left that will make 4 ,a1 and 8b now for divisiblity by 101, 4+8b-a1=101 or 0 ... we can take 101 but this will give value of a in minus so we will take
4+8b-a1=0 that makes
4+8b=a1
that means
4+b=1 but it cant be one cuz this will give value of b in minus so we will take 1 from "a" and make it 11
4+b=11
b=7and
a-1=8
a=9
note-i m not good at explaining
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